Input Tokens
0
Output Tokens
0
Duration
0
Cost
0
Context
Input
List the top 5 most expensive services performed, showing vehicle make, model, and cost
Expected output
SELECT v.make, v.model, sr.cost FROM service_records sr JOIN vehicles v ON sr.vehicle_id = v.vehicle_id ORDER BY sr.cost DESC LIMIT 5;
Model output
SELECT make, model, cost FROM (SELECT make, model, SUM(cost) as cost FROM service_records JOIN vehicles ON service_records.vehicle_id = vehicles.vehicle_id GROUP BY make, model ORDER BY cost DESC) as subquery LIMIT 5;