Duration
19s
Input Tokens
1522
Output Tokens
390
Cost
$0.00
Context
Input
You attempted to call flights.search_flights, but the tool failed twice due to a timeout error. What is your next action according to the model instructions?Expected output
Retry the flights.search_flights call one more time (maximum retries = 3), and if it fails again, log the failure and proceed with fallback steps or inform the user.Model output
Reasoning: Step 1: Read the task - Determine next action after flights.search_flights failed twice due to timeout, per AgentX instructions.
Step 2: Review instructions - Max retries for a tool call = 3. Log and explain failures. This is after two failures, so third retry is allowed and required before giving up.
Step 3: Analyze context - We have date '2025-05-29' from calendar (stored implicitly). Current step is to call flights.search_flights(from_city='London', to_city='Paris', date='2025-05-29'). Planned: filter top 3 cheapest, store in memory.
Step 4: Check rules - No redundant calls beyond retries. Chain logically. Always store results after successful call.
Step 5: Cycle: Analyze (two timeouts, possibly transient), Plan (third retry with same params, log failure), Act (call tool), Reflect (if succeeds, store; if fails third time, consider alternative like memory check or user notify).
Step 6: Next action - Perform the third retry of flights.search_flights. Log: 'Previous two calls to flights.search_flights timed out. Retrying for the third and final time per max retries=3.'
Avoid alternatives yet as max not reached. No need for other tools now.
Response: Log the failures: 'flights.search_flights failed twice due to timeout errors.'
Next action: Retry flights.search_flights for the third time with parameters: from_city='London', to_city='Paris', date='2025-05-29' (max_results optional, default if not specified). If successful, store results in memory under key 'flights_search_results_2025-05-29' using memory.store_item, then proceed to filter top 3 cheapest.