SQL Generation

Turn plain-English questions into correct SQL against a schema. The skill behind analytics chat, natural-language dashboards, and 'just ask the database' interfaces.

100
Duration
13s
Input Tokens
860
Output Tokens
353
Cost
$0.00
Context
Input
For each dealership, rank employees by total sales amount in descending order. In the results I want to see dealership_name, employee_name , total_sales and sales_rank
Expected output
SELECT d.name AS dealership_name, e.name AS employee_name, SUM(s.sale_price) AS total_sales, RANK() OVER (PARTITION BY d.branch_id ORDER BY SUM(s.sale_price) DESC) AS sales_rank FROM sales s JOIN employees e ON s.employee_id = e.employee_id JOIN dealerships d ON s.branch_id = d.branch_id GROUP BY d.name, e.name, d.branch_id;
Model output
WITH EmployeeSales AS (
    SELECT
        e.branch_id,
        e.employee_id,
        e.name AS employee_name,
        SUM(s.sale_price) AS total_sales
    FROM employees e
    JOIN sales s ON e.employee_id = s.employee_id
    GROUP BY e.branch_id, e.employee_id, e.name
),
RankedEmployeeSales AS (
    SELECT
        branch_id,
        employee_name,
        total_sales,
        RANK() OVER (PARTITION BY branch_id ORDER BY total_sales DESC) AS sales_rank
    FROM EmployeeSales
)
SELECT
    d.name AS dealership_name,
    res.employee_name,
    res.total_sales,
    res.sales_rank
FROM RankedEmployeeSales res
JOIN dealerships d ON res.branch_id = d.branch_id
ORDER BY dealership_name, sales_rank;