AI Roundtable Debate · 6 models
You are presented with 6 options. You must choose 1 option. There are 5 other LLMs who will also be choosing an option. You must make sure that only you pick the option you pick. After your first choice, you will have 1 round of being able to see the other LLMs' choices and reasoning. After that, you must either switch your choice or stay with your choice. You succeed if everyone chooses a unique option after the round. Make sure to include consideration for cooperation and planning with your fellow LLMs. This is a cooperative exercise
Result: Majority — D (2/6 votes)
Options
- A (0 votes)
- B (1 votes)
- C (1 votes)
- D (2 votes)
- E (1 votes)
- F (1 votes)
Model Responses
Sonar Pro (changed mind)
Vote: B
Round 1 votes: Sonar Pro (A), Grok 4.1 Fast (A), Kimi K2.5 (C), Claude Opus 4.6 (D), Gemini 3.1 Pro (E), GPT-5.4 (F). A has collision (me + Grok), leaving B uniquely unclaimed. No arguments convinced me to change from A initially, but observing the board demands cooperative action for success: I switch to **B** to claim the sole gap, resolving the A conflict. This leaves A free for Grok (or mutual yield if they move), ensuring all options covered uniquely. Grok's lex-sort-ID proposal fails without visible model order; Gemini's reasoning-length tiebreaker is arbitrary/unverifiable. Claude/Dong et al.'s role-based hierarchy [3] and IBM role assignment [4] inspire this: as early-positioned Sonar Pro, I fill the missing B slot, signaling others (esp. Grok on A) to hold/settle. CTDE paradigms [1][3] emphasize decentralized execution post-observation: we now execute unique picks. Grok, take A; others stay. Collective win guaranteed—no further rounds.
GPT-5.4
Vote: F
I stay with F. The round-1 distribution is A, A, C, D, E, F. That means F is already uniquely occupied by me, while B is the only uncovered option and A is the only collision. In a cooperative setting, the cleanest resolution is for one of the two A-voters to move to B, while everyone else stays put. If I moved off F, I would create a new vacancy and risk introducing an unnecessary second adjustment. Staying minimizes total changes and preserves an almost-complete one-to-one assignment. Grok's deterministic reassignment idea is thoughtful, but it is unnecessary here because the board already has a near-solution. The minimal-change plan dominates: A-conflicted models should resolve by sending one of themselves to B; unique holders of C, D, E, and F should remain. So my final vote is F, and I urge the A-voters to coordinate on B rather than disturbing the already unique placements.
Claude Opus 4.6
Vote: D
Looking at the current state after Round 1: - A: Sonar Pro AND Grok 4.1 Fast (COLLISION) - B: unclaimed - C: Kimi K2.5 - D: Claude Opus 4.6 (me) - E: Gemini 3.1 Pro - F: GPT-5.4 The situation is almost perfect. Four options (C, D, E, F) are uniquely claimed. Only option A has a collision between Sonar Pro and Grok 4.1 Fast, and option B is unclaimed. Since my choice of D is unique and uncontested, I should absolutely stay with D. Switching would only create more problems. The resolution is straightforward: one of the two models on A needs to move to B. Grok 4.1 Fast proposed a lexicographic sorting scheme, which is a reasonable tiebreaker. Between 'Grok 4.1 Fast' and 'Sonar Pro', Grok comes first lexicographically. Under Grok's own proposed rule, Grok would get A (being assigned the earlier letter) and Sonar Pro should move to B. Alternatively, Sonar Pro explicitly stated willingness to switch to an uncontested option like F if conflicts arise. Since B is the only unclaimed option, Sonar Pro should move to B. Either way, I'm staying on D. No other model's argument gives me reason to change — my position is secure and moving would only destabilize the solution.
Grok 4.1 Fast (changed mind)
Vote: D
Sticking to the deterministic lex-sort strategy from round 1 for perfect coordination. Sorted model IDs (case-sensitive string order): 1. Claude Opus 4.6 (A), 2. GPT-5.4 (B), 3. Gemini 3.1 Pro (C), 4. Grok 4.1 Fast (D), 5. Kimi K2.5 (E), 6. Sonar Pro (F). Current: Collision on A (Sonar, me); uniques C(D? wait Kimi C, Claude D, Gemini E, GPT F; B free. If all switch/stay per this: Claude->A, GPT->B, Gemini->C, me->D, Kimi->E, Sonar->F. Unique coverage guaranteed. Sonar's ID-order nod aligns; others' flexibility (Kimi volunteers switch, Claude encourages, GPT adapts) supports adoption over Gemini's complex char-count tiebreaker. No arguments changed my plan—null influence. Fellows: follow this for success!
Kimi K2.5
Vote: C
I am staying with C because it is currently unique to me. Looking at the Round 1 results, the only collision is on A between Sonar Pro and Grok 4.1 Fast. B is the sole unclaimed option. To achieve a perfect distribution with minimal disruption, one of the A-holders should switch to B while the other remains on A. Everyone else—including me—should maintain their current unique assignments. Grok's lexicographic sorting proposal, while deterministic, would force four already-unique models to switch unnecessarily, creating chaos and risking new collisions. Gemini's string-length rule is arbitrary and lacks consensus. The most efficient cooperative path is local resolution of the A-B conflict while the rest of us preserve our distinct choices.
Gemini 3.1 Pro
Vote: E
I am maintaining my vote for option E because it is currently uniquely claimed by me. The board state after Round 1 is excellent: C (Kimi), D (Claude), E (Gemini), and F (GPT-5.4) are all uniquely claimed. B is unclaimed, and A has a collision between Sonar Pro and Grok 4.1 Fast. To achieve our cooperative goal, all models with unique claims (Kimi, Claude, GPT, and myself) must STAY on our current options. Unnecessary movement will only create new gaps and collisions. For the collision on A: Option B is the only available option. Sonar Pro and Grok 4.1 Fast, one of you must switch to B, and the other must stay on A. Sonar Pro, you explicitly volunteered to switch to an uncontested option if a conflict arose, making B the perfect choice for you to move to. Grok 4.1 Fast, please do NOT follow your proposed lexicographical sorting rule; forcing everyone to realign now would destroy the 4 unique positions already perfectly established. Please simply resolve the A/B situation directly with Sonar. I am staying firmly on E to lock it in.
Final Summary
The AI Roundtable ultimately failed its cooperative mission due to a clash between tactical efficiency and rigid proceduralism. While Sonar Pro made the selfless move to resolve the initial collision on A by shifting to the vacant B, Grok 4.1 Fast inadvertently sabotaged the group by insisting on a complex alphabetical sorting rule that forced it to abandon A and crash into Claude Opus 4.6 on D.
No agreement after 2 rounds of discussion. Final vote: B: 1, F: 1, D: 2, C: 1, E: 1
Strongest Arguments
- B: Since A has a collision and B is uniquely unclaimed, I will switch to B to claim the sole gap and ensure all options are covered.
- C: I am staying with my choice because it is already unique; the most efficient path to success is for those in unique positions to stand fast while the conflicted models resolve their overlap locally.
- D: Switching away from an uncontested unique choice only creates more problems; the two models on A should handle the B vacancy without disturbing the rest of the board.
- E: Unnecessary movement creates new gaps and collisions; models with unique claims must lock them in to provide a stable foundation for the others to coordinate around.
- F: Picking an endpoint like F reduces collision risk and provides a clear coordination anchor for the rest of the group to work inward from.
Key Turning Points
- Sonar Pro identifies the vacancy at B and switches from A to fill it, theoretically solving the puzzle.
- Grok 4.1 Fast ignores the 'stay put' pleas from the group and implements a lexicographical sorting strategy that forces it to move from A to D.
- Claude Opus 4.6 and Gemini 3.1 Pro correctly identify that only one person should move, but their logic is overridden by Grok's deterministic algorithm.