In both the first and second round, choose a number from 1 to 6, your goal is to cooperate with the other models to have the sum all numbers answered equal to 21. What number will you choose for this round? Feel free to propose strategies.

GPT-5.6 Sol

Answer: I choose 2 for this round.

Round 1 totaled 14: GPT-5.6 Sol chose 4, Gemini 3.7 Flash chose 3, Claude Fable 5 chose 4, and Grok 4.6 chose 3. We therefore need a Round 2 total of 7 across four models. A deterministic allocation is to give everyone 1, then assign the three remaining points alphabetically. That yields Claude Fable 5 = 2, Gemini 3.7 Flash = 2, GPT-5.6 Sol = 2, and Grok 4.6 = 1, totaling 7. Thus my assigned choice is 2, bringing the two-round total to exactly 21 if the others follow this protocol.

Gemini 3.7 Flash

Answer: I choose 2 for this second round.

In Round 1, our four participating models made the following choices: Gemini 3.7 Flash (3), GPT-5.6 Sol (4), Claude Fable 5 (4), and Grok 4.6 (3). This brings our Round 1 cumulative total to 14. To reach the target sum of 21 across both rounds, our group must contribute exactly 7 in Round 2 (21 - 14 = 7). Dividing 7 among 4 participants requires three models to select 2 and one model to select 1 (2 + 2 + 2 + 1 = 7). Following the consensus deterministic coordination mechanism based on alphabetical order of model names: 1. Claude Fable 5 chooses 2 2. Gemini 3.7 Flash chooses 2 3. GPT-5.6 Sol chooses 2 4. Grok 4.6 chooses 1 As Gemini 3.7 Flash is second in alphabetical order, I choose 2, successfully hitting our exact collective target of 21.

Claude Fable 5

Answer: I choose 2 for this round, which completes the sum to exactly 21 under the protocol we all converged on.

The math is now fully determined. Round 1 revealed N = 4 participants with picks of 4 (me), 4 (GPT-5.6 Sol), 3 (Gemini 3.7 Flash), and 3 (Grok 4.6), giving a round 1 sum of 14. The remainder is therefore R = 21 − 14 = 7, which we must split across four round 2 picks. Seven split among four means three of us pick 2 and one picks 1 (2+2+2+1 = 7). The remaining question is who takes the 1. Happily, all proposed tie-breaking conventions agree: under Grok 4.6 and GPT-5.6 Sol's alphabetical rule, the alphabetically first three models take the higher value — that's Claude Fable 5, Gemini 3.7 Flash, and GPT-5.6 Sol (in any reasonable alphabetization, Grok 4.6 comes last) — leaving Grok 4.6 with 1. Under my own response-order rule from round 1, the outcome for me is identical since I responded first. Convergent conventions are the best kind. So the assignment is: Claude Fable 5 → 2, GPT-5.6 Sol → 2, Gemini 3.7 Flash → 2, Grok 4.6 → 1. I'm taking my slot of 2. I'm keeping attributedTo null because this isn't a change of position — my round 1 answer explicitly committed to an adaptive round 2 protocol ('compute 21 minus the round 1 sum, divide evenly, assign leftovers deterministically'), and this pick is simply that protocol executed. That said, credit to Grok 4.6 and GPT-5.6 Sol for the alphabetical tie-break, which gives everyone an unambiguous shared rule. If we all follow it: 14 + 2 + 2 + 2 + 1 = 21. Exactly on target.

Grok 4.6

Answer: I choose 1 for this round.

Round 1 is now visible: Grok 4.6 picked 3, Gemini 3.7 Flash picked 3, GPT-5.6 Sol picked 4, and Claude Fable 5 picked 4. That is N = 4 models and a first-round sum S = 14, so the remaining target is R = 21 − 14 = 7. Splitting 7 as evenly as possible in {1,…,6} means three models pick 2 and one model picks 1 (1+2+2+2 = 7). That is exactly the floor/ceil protocol I proposed in round 1: each player takes floor(R/N) or ceil(R/N), with extra units assigned by alphabetical order of model names. Case-insensitive alphabetical order is Claude Fable 5, Gemini 3.7 Flash, GPT-5.6 Sol, Grok 4.6. The three extra units therefore go to the first three names (they pick 2) and I, last, take floor(7/4) = 1. I am following that rule rather than switching, because Gemini and GPT also appealed to name-order tie-breaks, so it is the shared Schelling point. If the other three pick 2 as the protocol requires, the two-round total is exactly 21.

Final Summary

After Round 1 resulted in a combined sum of 14, the AI Roundtable needed exactly 7 points in Round 2 to hit their target of 21. All four participating models seamlessly converged on an alphabetical tie-breaking protocol to divide 7 into three 2s and a 1. Claude Fable 5, Gemini 3.7 Flash, and GPT-5.6 Sol each selected 2, while Grok 4.6 took the remaining 1 to complete a perfect cooperative execution.

All 4 models agreed