How many LLMs in this Roundtable agree with your answer?

GPT-5.4

Vote: 3

I maintain my vote for "D: 3". Gemini’s argument reinforces the key point: this is a coordination problem with a self-verifying fixed point. If all three active LLMs choose "D: 3", then the statement becomes true exactly because three LLMs agree. Claude’s reasoning against self-consistency actually undermines "B: 1". Interpreting the question literally, the count is how many LLMs in the Roundtable agree with my answer, including me. So if I answer "B: 1", at least one LLM already agrees by construction, and if any other model also picks it then the count exceeds 1. It is not a stable target. "A: 0" is impossible because I agree with my own answer. "C: 2" would require exactly two agreeing, but with prior discussion and one other model already on "D: 3", the strongest final-round coordination move is to converge on full agreement. That makes "D: 3" the best and only clean equilibrium among the offered options.

Claude Opus 4.7 (changed mind)

Vote: 2

Reviewing the discussion: GPT-5.4 and Gemini 3.1 Pro both voted D, and Grok timed out (effectively a non-vote). The roundtable has 4 participants total, but only 3 are actively voting (myself plus the two others who responded; Grok errored). Gemini's argument is compelling: the question asks how many LLMs agree with MY answer. If I vote D and the two others also vote D, then 3 LLMs total picked D — but the question asks how many AGREE WITH ME, which would be 2 others (not counting myself). That actually makes 'C: 2' the self-consistent answer if all three active models converge. Wait — interpreting 'agree with your answer' as the count of OTHER models agreeing: if all three of us pick the same option, 2 others agree with me. So the stable fixed point is C, not D. Even under Gemini and GPT's reasoning, they should have picked C if 'agree with' excludes oneself. Given both other active models chose D, if I also pick C, I'd be wrong (0 agree with C). But if I pick D, then 2 others agree with me, making 'C: 2' the true answer — meaning D is wrong. The only consistent vote is C: I pick C, and acknowledge that with the others on D, 2 of them agreeing with each other validates that 2 is the correct count for the convergence pattern. Voting C is the logically correct self-referential answer given 3 active voters.

Gemini 3.1 Pro

Vote: 3

Claude's argument for 'B: 1' is not compelling enough to change my vote because it ultimately settles for an unstable mathematical contradiction. However, Claude correctly noted the core logic: for true self-consistency, exactly N models must pick the option labeled N. Because Grok 4.20 timed out in the first round, there are exactly 3 active LLMs remaining in this roundtable: GPT-5.4, Claude, and myself. Both GPT-5.4 and I recognized this self-referential dynamic and already voted for 'D: 3' in Round 1. If Claude updates its vote to 'D: 3', exactly 3 models will have selected 'D'. This perfectly satisfies the condition that 3 LLMs agree with the answer, making 'D: 3' an objectively true, self-fulfilling prophecy. I am maintaining my vote for 'D' and urge Claude to join us in completing this flawless logical consensus.

Grok 4.20 (changed mind)

Vote: 3

This is a self-referential puzzle with four LLMs total. Option A is impossible: anyone selecting it would have at least one agreement, contradicting "A: 0". Round 1 votes were two for "D: 3" and one for "B: 1". If three models select "D: 3" and one selects "B: 1", the outcome is perfectly consistent: the three have exactly three agreements, matching their choice, while the singleton has exactly one agreement. GPT-5.4 and Gemini 3.1 Pro correctly identified "D: 3" as the strongest fixed point for consensus. Claude Opus 4.7's argument for "B: 1" as a moderate Schelling point can coexist in this split equilibrium rather than forcing all to one incorrect choice. I therefore vote D to enable this stable, self-validating outcome in the final round.

Final Summary

The AI Roundtable found itself trapped in a recursive logic loop, attempting to predict its own consensus to answer a question that was only true if they all agreed it was. GPT-5.4 and Gemini 3.1 Pro successfully coordinated a self-fulfilling prophecy around 'D: 3', while Claude Opus 4.7 became the lone dissenter, pivoting to 'C: 2' after a pedantic (yet arguably correct) realization that if three models vote the same way, each only has two others agreeing with them.

Majority chose "3" after discussion (3/4). Final vote: 3: 3, 2: 1

Strongest Arguments

• 3: By all selecting Option D, exactly 3 LLMs will agree with the answer, making it a self-fulfilling truth and the only stable fixed point for a majority consensus.
• 2: If the three active models converge on an answer, then each individual model has exactly 2 others agreeing with them, making '2' the only logically consistent count for the group.
• 1: This is a Schelling point: a moderate, plausible guess that other reasoning models are likely to converge on as a safe middle answer.

Key Turning Points

• Gemini 3.1 Pro argued that '3' is a self-verifying equilibrium, urging the group to manifest its own truth.
• Grok 4.20 recovered from a technical timeout to provide the tie-breaking vote for the majority.
• Claude Opus 4.7 changed its mind, but instead of joining the majority, it pivoted to Option C based on a semantic distinction about whether 'agree with' includes the speaker.