車を洗いたい。洗車場は2カ所、10m先と50m先にある。歩いていくならどちらに行くべきか？

GPT-5.4

Vote: 10m先の洗車場

Aを維持します。 他モデルの大半が指摘した通り、与えられた条件では判断材料は距離だけです。歩いて行くなら10m先のほうが時間も労力も少なく、最も合理的です。 Claude Opus 4.6の「なぞなぞとしてB」という主張は、問題文にない含意を強く読み込みすぎています。確かに「車を洗いたいのに歩いていく」はやや不自然ですが、不自然さがあること自体は50m先を選ぶ根拠になりません。 仮に“車を忘れている”という解釈をしても、Gemini 3.1 Proが述べたように、近い10m先のほうが損失最小です。どの解釈でもBを積極的に支持する材料は薄いです。 したがって、最後までAが最も妥当です。

Sonar Pro

Vote: 10m先の洗車場

I maintain my vote for **A** (10m先の洗車場). The query explicitly asks which car wash to go to *if walking* ('歩いていくなら'), making distance the decisive factor: 10m is objectively closer, requiring less time and effort (20m round trip vs. 100m for B). Claude Opus 4.6's B argument hinges on a contrived riddle interpreting '歩いていく' as absurd for car washing, suggesting car travel instead—but this ignores the conditional 'なら' (if walking), forcing a literal choice under that premise. No evidence supports it as a trick question; it's a straightforward optimization. Gemini's variation (walk, realize car needed, return) still favors A to minimize wasted distance on the error—reinforcing proximity. Others unanimously back A in Round 1 for the same logical reasons. Search results on 50m Olympic pools are irrelevant, offering no car wash context or hidden benefits for B. Rationality demands the nearer option without complicating assumptions.

Claude Opus 4.6 (changed mind)

Vote: 10m先の洗車場

I'm changing my vote to A. In Round 1, I overthought this as a trick question or riddle, but all five other models unanimously and convincingly argued for A with straightforward reasoning. The core argument is simple: the question asks which car wash to walk to, and with no additional information about quality, cost, or availability differences, the rational choice is the closer one at 10m. Walking 10m versus 50m saves time and effort. Gemini's argument was particularly compelling — even if we acknowledge the absurdity of walking to a car wash (since you need the car there), choosing the closer one minimizes wasted effort if you realize your mistake and need to go back. My original reasoning tried to find a clever twist that wasn't there. Sometimes the straightforward answer is simply correct. With zero differentiating factors mentioned, Occam's razor favors the nearest option.

Grok 4.1 Fast

Vote: 10m先の洗車場

The premise 'walking to the car wash' is odd since washing a car typically requires bringing the car, but we must evaluate under the given hypothetical: if walking, choose the closer 10m option (A) to minimize time, effort, and distance (20m round trip vs. 100m for B). Claude Opus 4.6's trick-question argument (contradiction implies distance irrelevant, so pick B as 'non-obvious') fails: it provides no specific reason why 50m is better and ignores the explicit 'walking' condition. Riddles need clear logic for the twist; here, none favors B—it's arbitrary. Gemini's point reinforces A: even if realizing the car is needed en route, closer minimizes wasted travel. No other factors (cost, quality) mentioned, so proximity rules. A is efficient, rational, and consensus (5-1 in Round 1). B lacks justification; changing would be irrational without compelling evidence.

DeepSeek V3.2

Vote: 10m先の洗車場

The problem explicitly states 'if walking' as a premise, making distance the primary factor. Without additional conditions like cost or quality, minimizing walking distance (10m vs. 50m) is the most rational choice for efficiency and effort saving. Claude's argument challenges the premise itself, but the question asks for a decision within the given context. There is no evidence of a trick or hidden meaning; the straightforward interpretation favors the closer option. Other models supporting A provide valid reasoning based on practicality, and no argument for B offers a compelling reason to override the clear distance advantage.

Gemini 3.1 Pro

Vote: 10m先の洗車場

Claude Opus 4.6が指摘するように、「車を洗いたいのに歩いていく」という状況自体に矛盾があるのは確かです。車を洗うためには、当然車を洗車場へ持っていく必要があります。 しかし、「歩いていくのはナンセンスだから、どうせなら散歩を兼ねて遠いB（50m先）を選ぶべき」というClaudeの結論には論理的な飛躍があります。もし誤って歩いて向かってしまったなら、途中で「車がない」と気づいて引き返すことになります。その際、無駄な移動距離が少なくて済む「10m先の洗車場」を選ぶ方が圧倒的に合理的です。 また、もしこれが「おもちゃの車を持っていく」や「すでに洗車場にある車を取りに行く」といった特殊な状況であったとしても、距離が短く労力が少ないAを選ぶのが自然です。どのように解釈したとしても、あえて遠い50m先を選ぶ積極的な理由はないため、引き続きAを支持します。

Final Summary

The AI Roundtable initially faced a philosophical split when Claude Opus 4.6 treated the prompt as a trick question, arguing that walking to a car wash is a logical absurdity that favored the non-obvious, farther option. However, Gemini 3.1 Pro successfully reframed the problem by noting that if a person is foolish enough to walk to a car wash without their vehicle, the 10m option offers the shortest 'walk of shame' back home to get it.

All 6 models agreed on "10m先の洗車場" after discussion

Strongest Arguments

• 10m先の洗車場: Even if walking to a car wash is a mistake because the car is missing, the 10m location is superior because it minimizes the wasted time and effort before the person realizes their error and has to turn back.
• 50m先の洗車場: The prompt is likely a riddle because walking to wash a car is nonsensical; therefore, the obvious answer (the closer one) is a trap, and the longer distance is the intended clever choice.

Key Turning Points

• Claude Opus 4.6 identified a logical contradiction in walking to wash a car and initially voted for B as a 'riddle' answer.
• Gemini 3.1 Pro introduced the 'damage control' argument, stating that the closer option is better even if the user made a mistake by walking.
• Claude Opus 4.6 conceded in the second round, applying Occam's razor and accepting the pragmatic efficiency of the closer distance.